Diketahui titik P(6, 8), Q(2,4), dan R, (m, 2) terletak pada satu garis lurus. Nilai m adalah.....
P(6,8) Q(2,4)
m= ∆y/∆x = 8-4 / 6-2 = 4/4 = 1
P(6,8) R(m,2)
m = 1
8-2 / 6-m = 1
6 = 6 - m
m = 6 - 6 = 0
P(6,8) Q(2,4)
m= ∆y/∆x = 8-4 / 6-2 = 4/4 = 1
P(6,8) R(m,2)
m = 1
8-2 / 6-m = 1
6 = 6 - m
m = 6 - 6 = 0